If it's not what You are looking for type in the equation solver your own equation and let us solve it.
3x^2-12x-129=0
a = 3; b = -12; c = -129;
Δ = b2-4ac
Δ = -122-4·3·(-129)
Δ = 1692
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1692}=\sqrt{36*47}=\sqrt{36}*\sqrt{47}=6\sqrt{47}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-6\sqrt{47}}{2*3}=\frac{12-6\sqrt{47}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+6\sqrt{47}}{2*3}=\frac{12+6\sqrt{47}}{6} $
| 1/3x=4/5*(28-x) | | y2–8y+15=0 | | 136-8x=-32 | | 1/3x=4/5(28-x) | | ㅣxㅣ=12 | | 4u^2-40u+68=0 | | v^2-14v-29=0 | | 5x=4+20 | | 8x+9=7x+3 | | 3x^2-84x-57=0 | | -3x^2+78x+63=0 | | 4*s-5*s=27 | | 3x^2-6x-141=0 | | 4*m+2*m=66 | | 5*m+4*m=72 | | 4.3*x=3.8 | | x^2+10x-49=0 | | 24=-2(m=3)+m | | 3x+5-6x=20 | | 4x^2-81x+162=0 | | 3p/5p+1/5(40-p)=0 | | 2x-6=-40 | | 10n+0.3=0.1+0.3 | | 2k^2-32k=58 | | 12x(6)=2 | | -2x^2-48x+86=0 | | -2x-48x+86=0 | | x2-6=-13 | | 4p^2-16p-132=0 | | 3w^2+36w-3=0 | | 7+9x=-101 | | -100=7+9x |